本文详解如何为多个房间分别计算一组选定日期的总价格:对每个日期,若该房间存在对应特惠价格则采用,否则使用其默认价格,并汇总得出各房间的总价。
在酒店预订、共享住宿等场景中,常需根据用户选择的连续日期(如入住/退房区间),为多个可选房型分别计算总费用。关键逻辑在于:每个日期单独匹配房间的 options 中的特惠价;若未找到,则 fallback 到 default_price。错误实现(如复用全局累加变量 $price)会导致前一个房间的累计值污染后续房间结果——这正是原代码中 Room2 总价异常的根本原因。
以下为推荐的清晰、健壮且无副作用的实现方案:
$selectedDates = ['10-04-2025', '11-04-2025', '12-04-2025'];
$setRooms = [
[
'id' => 1,
'title' => 'Room1',
'default_price' => 50,
'options' => [
['date' => '12-04-2025', 'price' => 100],
['date' => '13-04-2025', 'price' => 200],
['date' => '14-04-2025', 'price' => 200],
]
],
[
'id' => 2,
'title' => 'Room2',
'default_price' => 120,
'options' => [
['date' => '11-04-2025', 'price' => 200],
['date' => '12-04-2025', 'price' => 300],
['date' => '13-04-2025', 'price' => 400],
]
],
];
$result = [];
foreach ($setRooms as $room) {
$total = 0;
foreach ($selectedDates as $date) {
// 精确匹配日期(字符串全等,避免时区/格式解析风险)
$matchedOption = null;
foreach ($room['options'] as $option) {
if ($option['date'] === $date) {
$matchedOption = $option;
break;
}
}
$total += $matchedOption ? $matchedOption['price'] : $room['default_price'];
}
$result[] = [
'id' => $room['id'],
'title' => $room['title'],
'total_price' => $total
];
}
print_r($result);✅ 输出验证:

? 关键注意事项:
该方案结构清晰、逻辑隔离、无副作用,可直接集成到 Laravel 或其他 PHP 项目中,是处理动态房态定价的典型实践范式。